x,3,1,12,8
If x is an integer, is the median of the 5 numbers shown greater than the average (arithmetic mean) of the 5 numbers?
1. x>6
2. x is greater than the median of the 5 numbers
oa tba
set problem
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- logitech
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I agree both with your spoiler request and E choice.cramya wrote:I get E)
OA,please?
Hi Ch,
Friendly request: If you could post the OA wiht the spoiler function going forward it would be much appreciated!
1) Insuf X can be 1000000000000 and the mean can;t be greater than the AV
2) Insuf - it only tells us that x > 12 and with the same logic in (1) it can be 10000000000000 and mean can't be greater than AV
LGTCH
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- praneeth
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Agree with the answer but the reasoning has to rule out a definite "No" to the question, as a definite "No" would make the statements sufficient as well.logitech wrote:I agree both with your spoiler request and E choice.cramya wrote:I get E)
OA,please?
Hi Ch,
Friendly request: If you could post the OA wiht the spoiler function going forward it would be much appreciated!
1) Insuf X can be 1000000000000 and the mean can;t be greater than the AV
2) Insuf - it only tells us that x > 12 and with the same logic in (1) it can be 10000000000000 and mean can't be greater than AV
To rule out a definite No:
From statement two, we basically know that if X is higher than the median, which implies that the median has to be 8. Since the sum of the four numbers given is 24, if X is 9 then the arithmetic average is 33/5 = less than 8 (the median), however if X is instead something large like 21, the arithmetic average is 45/5 = 9 (greater than 8 - the median). Therefore a definite "No" is not possible in this case.
Therefore answer is E.
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[quote="praneeth]Agree with the answer but the reasoning has to rule out a definite "No" to the question, as a definite "No" would make the statements sufficient as well.
To rule out a definite No:
From statement two, we basically know that if X is higher than the median, which implies that the median has to be 8. Since the sum of the four numbers given is 24, if X is 9 then the arithmetic average is 33/5 = less than 8 (the median), however if X is instead something large like 21, the arithmetic average is 45/5 = 9 (greater than 8 - the median). Therefore a definite "No" is not possible in this case.
Therefore answer is E.[/quote]
hi,
can u pls explain how the median is 8?
To rule out a definite No:
From statement two, we basically know that if X is higher than the median, which implies that the median has to be 8. Since the sum of the four numbers given is 24, if X is 9 then the arithmetic average is 33/5 = less than 8 (the median), however if X is instead something large like 21, the arithmetic average is 45/5 = 9 (greater than 8 - the median). Therefore a definite "No" is not possible in this case.
Therefore answer is E.[/quote]
hi,
can u pls explain how the median is 8?
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Logitech,logitech wrote:
2) Insuf - it only tells us that x > 12 and with the same logic in (1) it can be 10000000000000 and mean can't be greater than AV
Shouldnt stmt 2 give us x>8 instead of x>12? Am i missing something here?
- praneeth
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hi,jimmiejaz wrote:[quote="praneeth]Agree with the answer but the reasoning has to rule out a definite "No" to the question, as a definite "No" would make the statements sufficient as well.
To rule out a definite No:
From statement two, we basically know that if X is higher than the median, which implies that the median has to be 8. Since the sum of the four numbers given is 24, if X is 9 then the arithmetic average is 33/5 = less than 8 (the median), however if X is instead something large like 21, the arithmetic average is 45/5 = 9 (greater than 8 - the median). Therefore a definite "No" is not possible in this case.
Therefore answer is E.
can u pls explain how the median is 8?[/quote]
If X is smaller than 8 and larger than the median the numbers would look something like:
1, 3, X, 8 12
since there are only two numbers smaller than X, and two numbers greater than X no other number can be the median, i.e. X has to be the median which doesn't satisfy our assumption that X is greater than the median.
There are only two numbers smaller than 8 in the data set, therefore for X to be greater than the median X has to be greater than 8.
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hi praneeth,
thanks for the explanation. Actually, i got confused. In the post above yours, i had deduced the same that x>8 for x to be greater than the median. I asked x>8 and you wrote median = 8. both are different interpretations for the same thing.
cheers!!!!!
thanks for the explanation. Actually, i got confused. In the post above yours, i had deduced the same that x>8 for x to be greater than the median. I asked x>8 and you wrote median = 8. both are different interpretations for the same thing.
cheers!!!!!