Hi everybody, here is a questions. I got the answer but I would like to know your options. Thanks in advance.
Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9 b.12 c.14 d.15 e.60
ANS: E
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Combination / Permutation problem
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jessicamuniz
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Tryingmybest
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hrishikesh05
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C is the notation for combination
Check this link for more information on C
https://en.wikipedia.org/wiki/Mathematical_combination
Check this link for more information on C
https://en.wikipedia.org/wiki/Mathematical_combination
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Jeff@TargetTestPrep
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Amanda can select a ball in 3C1 = 3 ways and she can selected a board game in 6C3 = 6!/[3!(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2 x 1) = 20. So, the total number of ways is 3 x 20 = 60.jessicamuniz wrote:Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9
b.12
c.14
d.15
e.60
Answer: E
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