Did the first of the GMAT prep tests today and had some problems from the start with two word problems.
1. For a finite sequence of nonzero numbers, the number of variatinos in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6?
Alternatives: One, two, three, four or five.
Just can't wrap my head around this text. Don't want to give my faulty answer just yet...
2. In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the card by the next larger integer. If each possible product is between 15 and 200, then the least and greatest integers on the cards could be:
- 3 and 15
- 3 and 20
- 4 and 13
- 4 and 14
- 5 and 14
Looks like I'm gonna have to work on my word problems. Appreciate any help with these Q:s!
Word problem questions (deck of cards etc)
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Q1: Ans is 3.
Q2: Ans is 4 and 13.
Frankenstein is correct.
Q2: Ans is 4 and 13.
Frankenstein is correct.
Last edited by sgarnepudi on Sat Jul 09, 2011 9:51 am, edited 1 time in total.
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Hi,
Q1 is nothing but asking for sign changes. A sign change is + to -, and - to +
Consider 1,-3,2,5,-4,-6. sign changes from 1 to -3, -3 to 2 and 5 to -4
So, answer is three
Q2)Product of a number and next larger number means if you pick a number n, the product is n*(n+1)
Go from options,
if we pick 3, n(n+1) is 12 not in the range (15,200)
So, A,B are out
if n = 4, n(n+1) = 20 ..fine in the range (15,200)
if n = 13, n(n+1) = 182 ..fine in the range (15,200)
if n= 14, n(n+1) = 14*15 = 210 outside the range (15,200)
Hence, C
Q1 is nothing but asking for sign changes. A sign change is + to -, and - to +
Consider 1,-3,2,5,-4,-6. sign changes from 1 to -3, -3 to 2 and 5 to -4
So, answer is three
Q2)Product of a number and next larger number means if you pick a number n, the product is n*(n+1)
Go from options,
if we pick 3, n(n+1) is 12 not in the range (15,200)
So, A,B are out
if n = 4, n(n+1) = 20 ..fine in the range (15,200)
if n = 13, n(n+1) = 182 ..fine in the range (15,200)
if n= 14, n(n+1) = 14*15 = 210 outside the range (15,200)
Hence, C
Cheers!
Things are not what they appear to be... nor are they otherwise
Things are not what they appear to be... nor are they otherwise
Thank you! Great answer. I really need to get better translating text into equations... However, this piece of text just confuses me so much:Frankenstein wrote:Hi,
Q1 is nothing but asking for sign changes. A sign change is + to -, and - to +
Consider 1,-3,2,5,-4,-6. sign changes from 1 to -3, -3 to 2 and 5 to -4
So, answer is three
Q2)Product of a number and next larger number means if you pick a number n, the product is n*(n+1)
Go from options,
if we pick 3, n(n+1) is 12 not in the range (15,200)
So, A,B are out
if n = 4, n(n+1) = 20 ..fine in the range (15,200)
if n = 13, n(n+1) = 182 ..fine in the range (15,200)
if n= 14, n(n+1) = 14*15 = 210 outside the range (15,200)
Hence, C
"the number of variatinos in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative"
Guess I should ignore this part and just read:
"What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6? "
Need some practice with the word problems.
Thanks again.
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a (1,-3); (-3,2) ; (5,-4) hence 3.
b 15 < n(n+1) < 200
means,
n * (n+1) = 4*5 = 20
and 13*14 = 182.
4-13.
b 15 < n(n+1) < 200
means,
n * (n+1) = 4*5 = 20
and 13*14 = 182.
4-13.
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