The formula for the surface of a sphere is \(S=4\pi r^2.\) Two lead balls have radii \(3\) inches and \(6\) inches, respectively. A third ball has a surface area equal to the sum of the surface areas of the two smaller balls. What is the radius, in inches, of the third ball?
(A) \(3\sqrt{10}\)
(B) \(3\sqrt5\)
(C) \(36\pi\)
(D) \(45\pi\)
(E) \(180\pi\)
Answer: B
Source: GMAT Prep