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a) a, b, c
b) b, c, a
c) b, a, c
d) c, a ,b
e) c, b, a
Nice Approach!!rn4gmat wrote:If we simply do a square for all these three it can be seen that
c : 16 = 8 + 8
b : 8 + 2 (15)^1/2 .Here 2 (15)^1/2 will be less than 2(16)^1/2 which is equal to 8 hence this will be less than c.
a: 8 + 2 (12)^1/2.Here 2 (12)^1/2 will be less than 2(15)^1/2 hence this will be less than b.
hence the correct order will be : c,b,a.
c² = 8 + 2√16rn4gmat wrote:If we simply do a square for all these three it can be seen that
c : 16 = 8 + 8
b : 8 + 2 (15)^1/2 .Here 2 (15)^1/2 will be less than 2(16)^1/2 which is equal to 8 hence this will be less than c.
a: 8 + 2 (12)^1/2.Here 2 (12)^1/2 will be less than 2(15)^1/2 hence this will be less than b.
hence the correct order will be : c,b,a.
Thanks, KSTV. Would it be possible for you to clarify that portion just a little more? I kind of follow it, but also a little lost.c² = 8 + 2√16
b² = 8 + 2√15 8 = 3+5
a² = 8 + 2√12 8 = 2+6