Is quadrilateral ABCD a rhombus?
(1) Line segments AC and BD are perpendicular bisectors of each other.
(2) AB = BC = CD = AD
Rhombus
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Statement (1)csandeepreddy wrote:Is quadrilateral ABCD a rhombus?
(1) Line segments AC and BD are perpendicular bisectors of each other.
(2) AB = BC = CD = AD
Ac and BD are bisect each other at 90 degree, this is property of both square and a rohmbus. Insufficient.
Statement (2)
AB = BC = CD = AD
Same as above, could be a rohmbus or a square. Insufficient.
Combining (1) & (2)
Still it could a rohmbus or a square. Insufficient
Hence E. OA?
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For anyone who (like me) didn't remember what a rhombus is:
Rhombus - A parallelogram with four congruent sides
Rhombus - A parallelogram with four congruent sides