If a certain culture of bacteria increases by a constant

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If a certain culture of bacteria increases by a constant factor of x every y minutes, how long will it take for the culture to increase to ten-thousand times its original size?

1. x=10^y
2.In two minutes, the culture will increase to one hundred times its original size.

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by GMATGuruNY » Tue Sep 03, 2013 8:36 am
If a certain culture of bacteria increases by a constant factor of x every y minutes, how long will it take for the culture to increase to ten thousand times its original size.

1- x^(1/y)= 10
2 - In two minutes, the culture will increase to one hundred times its original size.
Statement 1: x^(1/y) = 10.
[x^(1/y)]^y = 10^y.
x = 10^y.
Since 10,000 = 10�, x=10,000 when y=4.
Thus, it will take y=4 minutes for the culture to increase by a factor of x=10,000.
SUFFICIENT.

Statement 2: In two minutes, the culture will increase to one-hundred times its original amount.
Thus, in 4 minutes, the culture will increase to 100*100 = 10,000 times its original size.
SUFFICIENT.

The correct answer is D.
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by [email protected] » Tue Sep 03, 2013 1:26 pm
Hi bagdb@mba,

There's an alternative way to deal with Fact 1 (that I think that both Mitch and I are fans of):

Let's TEST values:

We're told that x is the constant factor of increase and y is the number of minutes per increase.

Fact 1 tells us that x = 10^y

If y = 1 minute
then x = 10 times bigger

Starting B bacteria
After 1 minute = 10B
After 2 minutes = 100B
After 3 minutes = 1,000B
After 4 minutes = 10,000B

If y = 2 minutes
then x = 100 times bigger

Starting B bacteria
After 2 minutes = 100B
After 4 minutes = 10,000B

You'll notice that the pattern leads to 4 minutes each time. Consistent = SUFFICIENT

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by royrijit1 » Sat Sep 05, 2015 2:36 am
Dear Experts/Moderators,

I am comparatively weak in such concepts(relative increases in populations). Request you to please post few similar questions solving which I can master this topic.
Thanks a lot in advance!

-RR1

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by [email protected] » Sat Sep 05, 2015 9:48 am
Hi royrijit1,

This question involves a 'geometric progression', which is relatively rare on Test Day (you probably won't see it at all). You WILL see questions that involve sequences, percentage increases/decreases and percentage change though (and you've probably already seen these concepts in the materials that you're using).

How long have you been studying?
What practice materials have you been using?

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by Max@Math Revolution » Sat Sep 05, 2015 9:37 pm
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.


If a certain culture of bacteria increases by a constant factor of x every y minutes, how long will it take for the culture to increase to ten-thousand times its original size?

1. x=10^y
2.In two minutes, the culture will increase to one hundred times its original size.


Since there are 2 variables (x,y) in the original condition, we need 2 equations to match the number of variables and equations. We have 1 each in 1) and 2), therefore C is likely the answer.
Using both 1) & 2) together,
In case of 1), x=10^6. Since the value is multiplied by 10^6 every 6 minute, the answer is 6 minute.
In case of 2), since the value is multiplied by 100 every 2 minute, it's 10,000times for 4 minutes and 1,000,000 for 6 minutes. Since 1) = 2), The answer is D.


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