Playing mixed doubles

shankyrams wrote:I think the answer is 105.
If there are X*Y people who are put in X groups containing Y people each the this can be done in [ (X*Y) ! / ((X!)*(Y^X)) ] ways.

This is a great way of doing it if we can

(1) identify the problem and remember the formula in the heat of the test

(2) be careful in not confusing some other problem as this problem and end up with the wrong answer.

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anayak: Junior | Next Rank: 30 Posts; Posts: 17; Joined: Sun Jun 08, 2008 10:30 pm

by anayak » Tue Jun 17, 2008 7:18 pm

Stuart, Great Explanaiton

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