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How many solution has (x^2+1)/(x-1)=x?

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How many solution has (x^2+1)/(x-1)=x?

by monge1980 » Wed Sep 14, 2011 6:54 am
if x not equal to 1, how many solution has (x^2+1)/(x-1)=x?

A) one
B) two
C) three
D) four
E) more than four
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by shankar.ashwin » Wed Sep 14, 2011 7:04 am
(x^2+1)=(x^2-x)
x=-1.

IMO (A)
monge1980 wrote:if x not equal to 1, how many solution has (x^2+1)/(x-1)=x?

A) one
B) two
C) three
D) four
E) more than four
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by monge1980 » Wed Sep 14, 2011 7:08 am
That's correct I think. This question appeared in my last official test, as a first question. I answered A) ...
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by schreze » Wed Sep 14, 2011 7:47 am
(x^2 + 1) / (x-1) = x

=>x^2+1 - x^2+1x = 0
==> x = -1
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