pencils - Trap Q
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the attachments in this post are quite large. I am reattaching as word documents. Also, apologies for incorrectly putting this into the PS Forum
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23 cent pencils & 21 cent pencils
23 cent pencils ?
Statement I
total number of pencils 6
we dont know the exact amount.
insufficient.
Statement II
total amount 130
21x + 23y = 130
remember x and y has to be integers and after multiplying the unit digits should add to 0.
This can only be done one way
when x=4 and y=2
21*4 = 84
23*2 = 46
84+46=130
Sufficient.
Hence B is the answer.
all the best.
23 cent pencils ?
Statement I
total number of pencils 6
we dont know the exact amount.
insufficient.
Statement II
total amount 130
21x + 23y = 130
remember x and y has to be integers and after multiplying the unit digits should add to 0.
This can only be done one way
when x=4 and y=2
21*4 = 84
23*2 = 46
84+46=130
Sufficient.
Hence B is the answer.
all the best.
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statement 1 . insufficientLSB wrote:the attachments in this post are quite large. I am reattaching as word documents. Also, apologies for incorrectly putting this into the PS Forum
statement 2 . since 130 is not a factor of either 23 or 21... she would have definitely atleast 1 of each pencil.
now we know 130/23 <n< 130/21
n must be a integer so its 6.
assume she bought X pencils for 23 cents..
she wud have bought 6-X for 21
therefore
23x + 21 ( 6 – x)= 130
hence X = 2.
hence B
Hope that helps
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Makes sense. I guess you can convert the equation into having one variable. I got the right answer (it was a sledgehammer approach though)
Was just unsure how we can have only one equation that solves for two variables. Thanks guys.
Was just unsure how we can have only one equation that solves for two variables. Thanks guys.
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I think the key thing to realise here is that this question is also testing your knowledge of digits ... as parallel_chase pointed out.
Essentially, with statement 2 we have to figure out how many 23's and how many 21's we can fit into 130.
This question has similarities to the following question:
https://www.beatthegmat.com/word-transla ... 15309.html
Essentially, with statement 2 we have to figure out how many 23's and how many 21's we can fit into 130.
This question has similarities to the following question:
https://www.beatthegmat.com/word-transla ... 15309.html