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Jason's salary
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Rahul@gurome
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Let Jason's salary be x in 1995 and Karen's salary be y in 1995.
So in 1998 their respective salaries were x+(xp/100) and y+(yp/100) or x(100+p)/100 and y(100+p)/100.
The question is asking for the value of p.
First consider statement (1) alone.
It means y-x = 2000.
Since nothing is being said about p, this information is not sufficient to answer the question.
Next consider statement (2) alone.
It means y(100+p)/100 - x(100+p)/100 = 2440 or {(100+p)/100}*(y-x) = 2440.
Again this information alone is not sufficient to answer the question.
Next combine both the statements together and check.
So we get two equations.
y-x = 2000.
and {(100+p)/100}*(y-x) = 2440.
On dividing second equation by first one we get (100+p)/100 = 2440/2000.
Or 100+p = 122 or p = 22.
So both statements together are sufficient to answer the question.
The correct answer is hence (C).
So in 1998 their respective salaries were x+(xp/100) and y+(yp/100) or x(100+p)/100 and y(100+p)/100.
The question is asking for the value of p.
First consider statement (1) alone.
It means y-x = 2000.
Since nothing is being said about p, this information is not sufficient to answer the question.
Next consider statement (2) alone.
It means y(100+p)/100 - x(100+p)/100 = 2440 or {(100+p)/100}*(y-x) = 2440.
Again this information alone is not sufficient to answer the question.
Next combine both the statements together and check.
So we get two equations.
y-x = 2000.
and {(100+p)/100}*(y-x) = 2440.
On dividing second equation by first one we get (100+p)/100 = 2440/2000.
Or 100+p = 122 or p = 22.
So both statements together are sufficient to answer the question.
The correct answer is hence (C).
Rahul Lakhani
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https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
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sumanr84
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------------------------1995------------------------- 1998
J's Salary-------------X-------------------------- X(1+.0p)
K's Salary-------------Y--------------------------- Y(1+.0p)
Statement 1 : Y - X = 2000 -> No way to find p . Insufficient
Statement 2 : Y(1+.0p) - X(1+.0p) = 2440
(1+.0p) ( Y - X ) = 2440 -> No way to find p. Insufficient
1 and 2 together,
Since, we have ( Y-X ) from eq 1. We can plug in 2 to get "p"...sufficient
J's Salary-------------X-------------------------- X(1+.0p)
K's Salary-------------Y--------------------------- Y(1+.0p)
Statement 1 : Y - X = 2000 -> No way to find p . Insufficient
Statement 2 : Y(1+.0p) - X(1+.0p) = 2440
(1+.0p) ( Y - X ) = 2440 -> No way to find p. Insufficient
1 and 2 together,
Since, we have ( Y-X ) from eq 1. We can plug in 2 to get "p"...sufficient
I am on a break !!
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aks16189
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Hi, both of you have explained very nicely but there is a much easier way to do this...
in 1995 let jason's salary b x so Karen is x+2000
now in 1998 both get p% increase so,
Jason= px and Karen=p(x+2000)
the diff is nw 2440 so,
p(x+2000)-px = 2440
=> px+2000p-px=2440
=>2000p=2440
=>p=1.22
and it is clear that both statements are needed to form 2 equations.
in 1995 let jason's salary b x so Karen is x+2000
now in 1998 both get p% increase so,
Jason= px and Karen=p(x+2000)
the diff is nw 2440 so,
p(x+2000)-px = 2440
=> px+2000p-px=2440
=>2000p=2440
=>p=1.22
and it is clear that both statements are needed to form 2 equations.
