Set

This topic has expert replies
User avatar
Master | Next Rank: 500 Posts
Posts: 435
Joined: Mon Mar 15, 2010 6:15 am
Thanked: 32 times
Followed by:1 members

Set

by eaakbari » Fri Nov 09, 2012 1:05 pm
In a college, where every student follows at least one of the three activities- drama, sports, or arts- 65% follow drama, 86% follow sports, and 57% follow arts. What can be the maximum and minimum percentage of students who follow
· all three activities
· exactly two activities
Whether you think you can or can't, you're right.
- Henry Ford

Senior | Next Rank: 100 Posts
Posts: 85
Joined: Mon Nov 12, 2012 11:12 am
Thanked: 8 times
Followed by:2 members

by Anindya Madhudor » Tue Nov 13, 2012 9:46 am
Let's make several assumptions.

Total number of students: 100.
Students with all three activities: x:
Students with drama and sports but not all three activities: a
Students with arts and drama but not all three activities: b
Students with arts and sports but not all three activities: c

Which means, only drama= 65-a-b-x
Only sports= 86-a-c-x
Only arts= 57-b-c-x

All students must add to 100 as stated by the first statement.

So, 65+ 86-a-c-x+c + 57-b-c-x=100
This gives, (a+b+c)+2x=108

You get max of all three activities when a+b+c=0, which gives x=54%
You get min of all three activities when a+b+c=92, which gives x=8% (this needs a bit of trial and error, but this is the only possible combination for the above equation to hold good for min value of x).