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by vladmire » Thu Jan 08, 2009 6:38 am
If a2 = 2a1 + 3 and a3 = 4a2 + 32, then in terms of a1, a1 + a2 + a3 =
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by sonu_thekool » Thu Jan 08, 2009 6:52 am
a1 + a2 + a3 (Question asks us to answer the result in terms of a1) where a2 = 2a1 + 3 and a3 = 4a2 + 32.

= a1 + (2a1 + 3) + (4a2 + 32)

= 3a1 + 4(2a1 + 3) + 35

= 3a1 + 8a1 + 12 + 35

= 11a1 + 37

Hope this helps.
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by rajataga » Thu Jan 08, 2009 9:42 am
Just one minor correction,

it is....

11a1 + 47
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