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by vivek.kapoor83 » Tue Jan 06, 2009 6:45 am
help..i could figure out 1 no. 64...but its not correct
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by sonu_thekool » Tue Jan 06, 2009 7:32 am
It should be 2.

Choice 'C'. The two numbers are 64 and 96.

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by drewd313 » Tue Jan 06, 2009 8:05 am
sonu_thekool wrote:It should be 2.

Choice 'C'. The two numbers are 64 and 96.
Thats great, but what is the best way to go about solving this problem?

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by sonu_thekool » Tue Jan 06, 2009 10:16 am
Since they are asking us to find a 2-digit number with a length of 6 - we need to find numbers from 10-99 with the prime factors.

Since 2 is the lowest prime, try 2x2x2x2x2x2 = 6 factors of 2 = 64

Next try replacing one of the 2s with the next high prime number 3:
2x2x2x2x2x3 = 5 factors of 2 and one 3 = 96

Since we only need numbers from 10-99 no other number with 6 factors would be eligible.

Hope this helps.

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by logitech » Tue Jan 06, 2009 5:23 pm
Think about all the small primes, which ones will you keep it under 100 when you have 6 of them ?

2x2x2x2x2x2 = 64 is a good start.

Our next prime is 3

We can try to replace one of the 2's and try

2x2x2x2x2x3 = 96

This is very close to our border line of 99. and we know that if we ever replace another 2 with 3 , we will cross that line so we should stop here and choose TWO.
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by drewd313 » Tue Jan 06, 2009 6:22 pm
Thanks for the responses.

This is actually the approach I took when doing the practice test. However, I had forgotten that 2 was a prime number for some reason and tried it with all 3's which results in a number bigger than 100. But, I understand it now thanks.

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by vivek.kapoor83 » Tue Jan 06, 2009 8:45 pm
Good explantion Logitech