If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area

This topic has expert replies
Moderator
Posts: 2058
Joined: Sun Oct 29, 2017 4:24 am
Thanked: 1 times
Followed by:5 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area of the triangle?

A. 30
B. 36
C. 48
D. 60
E. 65

Answer: A

Source: Magoosh

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 7311
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members
M7MBA wrote:
Thu Nov 05, 2020 8:31 am
If a triangle in the \(xy\)-coordinate system has vertices at \((-2 , -3), (4, -3)\) and \((28, 7),\) what is the area of the triangle?

A. 30
B. 36
C. 48
D. 60
E. 65

Answer: A

Solution:

Since (-2, -3) and (4, -3) are on a horizontal line, the base of the triangle is 4 - (-2) = 6. The height of the triangle is the vertical distance from (28, 7) to the extension of the base, i.e., from (28, 7) to (28, -3). Therefore, the height is 7 - (-3) = 10, and the area of the triangle is ½ x 6 x 10 = 30.

Answer: A

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage