What is the perimeter of the triangle?
![Image](https://s2.postimage.org/XkPrA.jpg)
To use 30 - 60 - 90 triangle property we have to find out such a triangle firstmoney9111 wrote:do we not use anything re: 30 - 60 - 90 triangle where the ratio is:
X, X sqrt(3), 2X?
In such a case, the radius of circle, say r, happens to be 2/3 of one median of the inscribed equilateral triangle of side a. For the length of one median of this inscribed equilateral triangle of side a, we can quickly form a 30-60-90 triangle with a as the side opposite to the right angle, and hence a √3/2 will be each median, whose 2/3 is the radius of circle.
ajith wrote:To use 30 - 60 - 90 triangle property we have to find out such a triangle firstmoney9111 wrote:do we not use anything re: 30 - 60 - 90 triangle where the ratio is:
X, X sqrt(3), 2X?
The Origin, One Vertex, Center of the chord is such a triangle
For simplicity let me call the center O, vertex A and center of the chord E
Angle OAC =30; AOE is 60 and OEA is 90, further OA is 4 (radius)
now OE =2x =4; AE =2Sqrt(3)
AB = 2*AE = 4sqrt(3); perimeter is 3AB =12sqrt(3)
tata wrote:Money9111, Ajith,
I am using the same approach for 30-60-90 ( 1-SQRT3-2) triangle for which the new ratio is (a-2*4-c) Where c is the side of the equilateral triangle. Using this the side of the triangle comes out to be 16*SQRT(3) and perimiter is 3*16*SQRT(3)
I guess I am doing something wrong, Ajith can you please explain with the figure. The way I figured is draw a perpendicular from one vertex to a side of the triangle, this will make a 30-60-90 triangle, with side opposite 60 degree angle is the diameter, 8 in this case, and side opposite 90 degree angle is side of equilateral triangle.