a certain list of 100 data has an average of 6 and standard deviation d, where d is a positive. Which of the following pairs of data when added to the list must result in a list of 102 data with standard deviation less than d?
-6 and 0
0 and 0
0 and 6
0 and 12
6 and 6
ans E
PREP TEST 2
This topic has expert replies
The standard deviation of a list would come down if the data points are closer to the mean.
The mean of the given list is 6 so the data pair 6 and 6 is closest (amongst the given options) to the mean and thus reduces the SD of the entire list (when added to the list)less than the current SD.
The mean of the given list is 6 so the data pair 6 and 6 is closest (amongst the given options) to the mean and thus reduces the SD of the entire list (when added to the list)less than the current SD.
-
- Legendary Member
- Posts: 594
- Joined: Thu Aug 14, 2008 11:51 pm
- Thanked: 12 times
sd = sqrt { [(x-x1)^2 + (x-x2)^2 + .... ]/N}
X - mean
x1 is the frist number , x2 is the second.. etc
N = total numbers
Now our aim is to decrease the SD when 2 new number are added...
N will be increased from 100 to 102
x =6..
So not to increase the sum in numerator.. we can add to numbers as 6,6..
as x-6 = 6-6 =0 in both cases but denominator has increased.. thus the overall SD has decreased....
X - mean
x1 is the frist number , x2 is the second.. etc
N = total numbers
Now our aim is to decrease the SD when 2 new number are added...
N will be increased from 100 to 102
x =6..
So not to increase the sum in numerator.. we can add to numbers as 6,6..
as x-6 = 6-6 =0 in both cases but denominator has increased.. thus the overall SD has decreased....