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GMAT Prep2?? (Medallion)
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Area of F+M = (pi)r^2
Area of M only = (r-s)^2pi
Area of the Frame =(pi)r^2 - (r-s)^2pi
=(pi)r^2 - {(r^2 - 2rs +s^2)pi}
=Pi (r^2 -r^2+2rs-s^2)
=(Pi)s(2r -s)
So, the answer is (pi)s(2r-s).
Hope this help.
Area of M only = (r-s)^2pi
Area of the Frame =(pi)r^2 - (r-s)^2pi
=(pi)r^2 - {(r^2 - 2rs +s^2)pi}
=Pi (r^2 -r^2+2rs-s^2)
=(Pi)s(2r -s)
So, the answer is (pi)s(2r-s).
Hope this help.
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