Can anyone help with this question
Equilateral triangle ABC is inscribed in a circle (points ABC are on the circle). IF the length of arc ABC is 24, what is the approximate diameter of the circle
A) 5
B) 8
C) 11
D) 15
E) 19
Equilateral triangle ABC is inscribed in a circle
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- logitech
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ABC creates three equal arcs on the circle. ( 60-60-60)recko2430 wrote:Can anyone help with this question
Equilateral triangle ABC is inscribed in a circle (points ABC are on the circle). IF the length of arc ABC is 24, what is the approximate diameter of the circle
A) 5
B) 8
C) 11
D) 15
E) 19
arc ABC : 24 so= Perimeter is: 3/2 x 24 = 36
36= 2pir OR Dpi ( since D=2r)
So, D = 36/pi ( pi=3.14...)
So D is slightly smaller than 12:
Hence C
LGTCH
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- dmateer25
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My approach was:
It is an equilateral triangle so there are three equal arcs.
The length of arc abc would be 2/3 of the circumference (circumference = pi(d)).
So this means:
24 = 2/3 * pi(d)
24/pi(d)= 2/3
72 = 2pi(d)
36 = pi(d)
36/pi = d
~11 = d
It is an equilateral triangle so there are three equal arcs.
The length of arc abc would be 2/3 of the circumference (circumference = pi(d)).
So this means:
24 = 2/3 * pi(d)
24/pi(d)= 2/3
72 = 2pi(d)
36 = pi(d)
36/pi = d
~11 = d
- Rich@VeritasPrep
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Take a look at this diagram:
https://etc.usf.edu/clipart/49900/49948/ ... ion_md.gif
Because it's an equilateral triangle, the lengths of arcs AB, BC, and AC are all equal. That means each is 1/3 of the total circumference of the circle.
arc ABC is formed by joining arcs AB and BC, which each represent 1/3 of the circumference. Therefore, arc ABC is 2/3 of the circumference.
https://etc.usf.edu/clipart/49900/49948/ ... ion_md.gif
Because it's an equilateral triangle, the lengths of arcs AB, BC, and AC are all equal. That means each is 1/3 of the total circumference of the circle.
arc ABC is formed by joining arcs AB and BC, which each represent 1/3 of the circumference. Therefore, arc ABC is 2/3 of the circumference.
Rich Zwelling
GMAT Instructor, Veritas Prep
GMAT Instructor, Veritas Prep
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A central angle is formed by two radii.recko2430 wrote:Can anyone help with this question
Equilateral triangle ABC is inscribed in a circle (points ABC are on the circle). IF the length of arc ABC is 24, what is the approximate diameter of the circle
A) 5
B) 8
C) 11
D) 15
E) 19
An inscribed angle is formed by two chords.
When an inscribed angle and a central angle intercept the same arc on the circle, the degree measurement of the inscribed angle is 1/2 the degree measurement of the central angle:
Circles display the following proportionality:
(Central Angle)/360 = (intercepted arc length)/circumference = (sector area)/(circle area)
Since 120/360 = 1/3, the intercepted arc in the circle above is 1/3 the circumference of the circle. The sector enclosed by the two radii is 1/3 the area of the entire circle.
Now here's a drawing of the problem above:
Let c = circumference.
Since angle A is 60 degrees, the corresponding central angle is 120 degrees. Since 120/360 = 1/3, arc BC = (1/3)c.
Using similar logic, arc AB = (1/3)c.
Thus, arc ABC = (2/3)c.
Since arc ABC = 24:
24 = 2/3c
c = 36.
Thus, �d = 36.
d ≈ 11.
The correct answer is C.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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