can someone tell me how to solve this problem.
thank you.
the OA is C
DS again!!
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1. x-y>-2
=> x>y-2
For y=1 we get x=-1 thus xy<0
For y=3 we get x=1 thus xy>0
Insufficient
2. x-2y<-6
=> x<2y-6
For y=1 we get x=-4 thus xy<0
For y=4 we get x=2 thus xy>0
Insufficient
Combining 1 and 2 gives
x>y-2 and x<2y-6
For y=1 we get -1<x and x<-4 thus for -ve value of x, xy<0
For y=4 we get x>2 and x<2 thus for +ve value of x, xy>0
Hence the solution is E.
Please correct me if i am wrong!
Thank you.
=> x>y-2
For y=1 we get x=-1 thus xy<0
For y=3 we get x=1 thus xy>0
Insufficient
2. x-2y<-6
=> x<2y-6
For y=1 we get x=-4 thus xy<0
For y=4 we get x=2 thus xy>0
Insufficient
Combining 1 and 2 gives
x>y-2 and x<2y-6
For y=1 we get -1<x and x<-4 thus for -ve value of x, xy<0
For y=4 we get x>2 and x<2 thus for +ve value of x, xy>0
Hence the solution is E.
Please correct me if i am wrong!
Thank you.
But the official answer is C..that is both the statements together are sufficient..gmatters2vj wrote:1. x-y>-2
=> x>y-2
For y=1 we get x=-1 thus xy<0
For y=3 we get x=1 thus xy>0
Insufficient
2. x-2y<-6
=> x<2y-6
For y=1 we get x=-4 thus xy<0
For y=4 we get x=2 thus xy>0
Insufficient
Combining 1 and 2 gives
x>y-2 and x<2y-6
For y=1 we get -1<x and x<-4 thus for -ve value of x, xy<0
For y=4 we get x>2 and x<2 thus for +ve value of x, xy>0
Hence the solution is E.
Please correct me if i am wrong!
Thank you.
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- Junior | Next Rank: 30 Posts
- Posts: 11
- Joined: Wed Aug 13, 2008 7:31 am
- Thanked: 4 times
Sorry Warlock,
I did a mistake while combining the two conditions.
When we combine the 2 conditions we get
y-2<x<2y-6
Please note that it can only be true when y>4
Also for every value of y>4, x>2
Thus xy>0 always.
So C should be the answer.
Apologize for the mistake.
I did a mistake while combining the two conditions.
When we combine the 2 conditions we get
y-2<x<2y-6
Please note that it can only be true when y>4
Also for every value of y>4, x>2
Thus xy>0 always.
So C should be the answer.
Apologize for the mistake.