try answering this one--OA to come later
In a basketball contest, players must make 10 free throws. Assuming a player has 90% chance of making each of his shots, how likely is it that he will make all of his first 10 shots?
Difficult Math Question #4
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- aim-wsc
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if u hv two throws:
ur chances of getting a right shot ll be 0.9 X 0.9=0.81
for 3: 0.9^3=0.729
... ...
SO ON for ten throws
probability=0.9 ^ 10
present the options pls.
ur chances of getting a right shot ll be 0.9 X 0.9=0.81
for 3: 0.9^3=0.729
... ...
SO ON for ten throws
probability=0.9 ^ 10
present the options pls.
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- aim-wsc
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yeah thats what i said.
but how can you expect a student know the value of 0.9 ^ 10 be 0.37 or something??
no i wont take this////
you gotta come up with options.
anyway
ya i know they hv not provided options..just answers right sigh!
no problem
hey
800guy,
you hv got 123 problems ...( it would take TWO MONTHS to finish...)
so be fast post 4-5 everyday instead....
but how can you expect a student know the value of 0.9 ^ 10 be 0.37 or something??
no i wont take this////
you gotta come up with options.
anyway
ya i know they hv not provided options..just answers right sigh!
no problem
hey
800guy,
you hv got 123 problems ...( it would take TWO MONTHS to finish...)
so be fast post 4-5 everyday instead....
Getting started @BTG?
Beginner's Guide to GMAT | Beating GMAT & beyond
Please do not PM me, (not active anymore) contact Eric.
Beginner's Guide to GMAT | Beating GMAT & beyond
Please do not PM me, (not active anymore) contact Eric.
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Chance of making a shot = 90%In a basketball contest, players must make 10 free throws. Assuming a player has 90% chance of making each of his shots, how likely is it that he will make all of his first 10 shots?
Probability of making a shot = 0.9
Thus probability of making all of first 10 shots = 10C10*(0.9)^10 = [spoiler](0.9)^10[/spoiler]
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I do not think you see sums like these on the gmat i.e .9 ^ 10. Do you really?
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Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.