The average of four distinct positive integers is 10. If the average of the smaller two of these four integers is 8, which of the following represents the maximum value of the largest integer?
13
14
15
16
17
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logitech
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a+b+c+d = 40
a+b = 16
so c+d = 24
We will make D MAX by finding the min C
Since all numbers are distinct and the average of the first two small numbers are 8, we can not choose 8 and 8 , but we can choose 7 and 9
so C can be minimim 10, which gives us 14 as the answer for D.
a+b = 16
so c+d = 24
We will make D MAX by finding the min C
Since all numbers are distinct and the average of the first two small numbers are 8, we can not choose 8 and 8 , but we can choose 7 and 9
so C can be minimim 10, which gives us 14 as the answer for D.
LGTCH
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DavoodBeater
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2*8 + X + Y = 4*10
X+Y=24
distinct number => the second smallest is at least 9.
=> for maximizing the largest, the third smallest must be 10.
=> 24-10=14
X+Y=24
distinct number => the second smallest is at least 9.
=> for maximizing the largest, the third smallest must be 10.
=> 24-10=14
