Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?
A.100p / (125 – p)
B.150p / (250 – p)
C.300p / (375 – p)
D.400p / (500 – p)
E.500p / (625 – p)
OA is [spoiler]"D". [/spoiler]Plz. explain
Revenue Problem
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p percent of newspapers were A
Let T be the total newspapers
No of A newspapers = percent of A newspapers(p percent given) * T
= p/100*T = pT/100
Revenue from all A newspapers
= No of A newspapers * cost of each A newspaper
= pT/100 * 1
= pT/100 (1)
Therefore 100-p percent is the B newspapers
No of B newspapers = percent of B newspapers(p percent given) * T
= 100-p /100*T
Revenue from all B newspapers
= No of B newspapers * cost of each B newspaper
= 100-p/100*T * 1.25 (2)
Total Revenue = pT/100 + (100-p) /100 * T * 1.25
(Adding (1) and (2))
r is the percentage of revenue obtained from A newspapers
= Revenue from all A newspapers / Total Revenue * 100
= [pT/100] / [pT/100 + (100-p) /100 * T * 1.25 ] * 100
Take T/100 OUT AS COMMON FACTOR FROM THE NUMERATOR AND DENOMINATOR
T/100 ( P ) DIVIDED BY T/100 (P+ ((100-P)*1.25)) * 100
T/100 cancels out
so we are left with P / P+125-1.25P *100
= 100P / 125-.25P
Multiplying the numerator and denominator by 4 we get
D) 400P / 500-P
Let T be the total newspapers
No of A newspapers = percent of A newspapers(p percent given) * T
= p/100*T = pT/100
Revenue from all A newspapers
= No of A newspapers * cost of each A newspaper
= pT/100 * 1
= pT/100 (1)
Therefore 100-p percent is the B newspapers
No of B newspapers = percent of B newspapers(p percent given) * T
= 100-p /100*T
Revenue from all B newspapers
= No of B newspapers * cost of each B newspaper
= 100-p/100*T * 1.25 (2)
Total Revenue = pT/100 + (100-p) /100 * T * 1.25
(Adding (1) and (2))
r is the percentage of revenue obtained from A newspapers
= Revenue from all A newspapers / Total Revenue * 100
= [pT/100] / [pT/100 + (100-p) /100 * T * 1.25 ] * 100
Take T/100 OUT AS COMMON FACTOR FROM THE NUMERATOR AND DENOMINATOR
T/100 ( P ) DIVIDED BY T/100 (P+ ((100-P)*1.25)) * 100
T/100 cancels out
so we are left with P / P+125-1.25P *100
= 100P / 125-.25P
Multiplying the numerator and denominator by 4 we get
D) 400P / 500-P
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i took 10 newspaper of A = 10$
4 newspaper of B = 15$
so, 14 newspaper =15$
r =revenue from A = 10/15*100 =66.6%
p= 10/14*100 =71%(Approx)
So. I putted the values of P in the eqn and tried to find out the r(Both in %)
d. ( 400*71)/429 ~ (i took it as 430)
caclualte it and comes out 66.4
As both the figures are in % . so this is correct
4 newspaper of B = 15$
so, 14 newspaper =15$
r =revenue from A = 10/15*100 =66.6%
p= 10/14*100 =71%(Approx)
So. I putted the values of P in the eqn and tried to find out the r(Both in %)
d. ( 400*71)/429 ~ (i took it as 430)
caclualte it and comes out 66.4
As both the figures are in % . so this is correct
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Let No of papers of A type = A
revenue from A type = A $
Let No of papers of B type = B
revenue from B type = 1.25B $
r (A + 1.25B) / 100 = A
p (A + B) / 100 = A
Solve both and you will have your ans
rA + 1.25rB = 100A
(100-r)A = 1.25rB
B/A = (100-r)/1.25r ---------------1
pA + pB = 100A
pB = (100-p)A
B/A = (100-p)/p ---------------2
equate both B/A
(100-r)/5r = (100-p)/4p
20/r - 1/5 = (100-p)/4p
20/r = (100-p)/4p + 1/5
20/r = (500-p)/20p
r = 400p/(500-p)
D ans
Hope this helps
revenue from A type = A $
Let No of papers of B type = B
revenue from B type = 1.25B $
r (A + 1.25B) / 100 = A
p (A + B) / 100 = A
Solve both and you will have your ans
rA + 1.25rB = 100A
(100-r)A = 1.25rB
B/A = (100-r)/1.25r ---------------1
pA + pB = 100A
pB = (100-p)A
B/A = (100-p)/p ---------------2
equate both B/A
(100-r)/5r = (100-p)/4p
20/r - 1/5 = (100-p)/4p
20/r = (100-p)/4p + 1/5
20/r = (500-p)/20p
r = 400p/(500-p)
D ans
Hope this helps
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I have a question for the last solution...
When the equations are set equal each other... why is the denominator r multiplied by 5 and the p by 4?
Thank you
When the equations are set equal each other... why is the denominator r multiplied by 5 and the p by 4?
Thank you
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A and B is the opnly new paper the shop keeper sold
so i plugin numbers ! (percentages any numebr wil do ) but i always take multiles of 10
total revenue is 50
r =50% and r =25% that is 25 newspapers
that is 25$ he earned by newpaper A
and and rest 50% that is p=50% from B that is numeber of B news papers is 20
so subsitute back p=20 and u sghould get r to be equal to 25
co incidence i always start with D (Manhatan)
400*20/500-20)
400*20/480
-->(20*20)/5
(5*20)/6
which satisfies the coindtion !!
this took more than 3 minutes !!
wats the source ???
Vishu
so i plugin numbers ! (percentages any numebr wil do ) but i always take multiles of 10
total revenue is 50
r =50% and r =25% that is 25 newspapers
that is 25$ he earned by newpaper A
and and rest 50% that is p=50% from B that is numeber of B news papers is 20
so subsitute back p=20 and u sghould get r to be equal to 25
co incidence i always start with D (Manhatan)
400*20/500-20)
400*20/480
-->(20*20)/5
(5*20)/6
which satisfies the coindtion !!
this took more than 3 minutes !!
wats the source ???
Vishu
1.25 is actually 5/4650 or bust wrote:I have a question for the last solution...
When the equations are set equal each other... why is the denominator r multiplied by 5 and the p by 4?
Thank you
(100-r)/1.25r
will become
4*(100-r)/5r
nwo take this 4 to denom of other expr
PS: I actually divided both equations by 4, which is same as we did above
![Smile :)](./images/smilies/smile.png)
Hope this helps!!
- logitech
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LETS KEEP IT SIMPLE! 8)gmat009 wrote:Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store’s revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?
A.100p / (125 – p)
B.150p / (250 – p)
C.300p / (375 – p)
D.400p / (500 – p)
E.500p / (625 – p)
OA is [spoiler]"D". [/spoiler]Plz. explain
[ P x 1 / ( 100 -P) 1.25 ] = R /(100-R)
R = 400 P / (500 – P)
Hint: This is a GMAT test, not a MATH midterm. Keep things simple! Keep things under 2 minutes!
LGTCH
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