Of the families in City X in 1994, 40 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 30 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998?
A. 50%
B. 52%
C. 56%
D. 70%
E. 74%
Percentage Help
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Lets approach this with nice numbers:
Of the families in City X in 1994, 40 percent owned a personal computer:
lets say there are a total of 100 families and 40 of them own a computer.
in 1998 that num was 30 percent greater than it was in 1994, or 130% of 40
1.3*40=52
total number of families in City X was 4 percent greater in 1998 than it was in 1994 or 104% of our 100 families = 104 families
52 of those owned a computer which is 50% Answer A
Of the families in City X in 1994, 40 percent owned a personal computer:
lets say there are a total of 100 families and 40 of them own a computer.
in 1998 that num was 30 percent greater than it was in 1994, or 130% of 40
1.3*40=52
total number of families in City X was 4 percent greater in 1998 than it was in 1994 or 104% of our 100 families = 104 families
52 of those owned a computer which is 50% Answer A
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usually putting numbers is an easier approach in these kind of problems but I've one morebhumika.k.shah wrote:yup ! thats how i got it
Just a thought - could there be any other approach whatsoever???
say X was population in '94 and Y in '98
so in '94 people having PC = 40/100*x = 0.4x
in '98 population was 4% greater than that in '94 so Y = X + 4/100*x = 1.04X
and in '98 number of PC owners was 30% greater than that in '94 which will be .40X + 30/100(.40*x) = .40X + .12X = .52x
now % of PC owners in '98 in terms of population in '98 = [.52X/1.04 x] * 100 = 1/2 * 100 = 50%
530->480->580
when posting a question don't post OA(even masked) before some discussion.
when posting a question don't post OA(even masked) before some discussion.
That's how I did it and is the easiest way I could think of.xilef wrote:Lets approach this with nice numbers:
Of the families in City X in 1994, 40 percent owned a personal computer:
lets say there are a total of 100 families and 40 of them own a computer.
in 1998 that num was 30 percent greater than it was in 1994, or 130% of 40
1.3*40=52
total number of families in City X was 4 percent greater in 1998 than it was in 1994 or 104% of our 100 families = 104 families
52 of those owned a computer which is 50% Answer A