Another xy DS question

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Another xy DS question

by crak.gmat » Sun Aug 24, 2008 11:52 am
is xy>0?

1. x-y>-2
2. x-2y<-6

The OA is C, would appreciate an explanation.

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by LSB » Sun Aug 24, 2008 3:04 pm
Question asks whether X & Y have the same sign. If they do XY>0. If they have different signs, then XY<0

from 1:
x-y>-2 it follows: x > y-2
This is not sufficient. All it says is that X>Y

from 2:
x-2y<-6 it follows: X < 2y-6
Also not sufficient. If X is negative Y could be positive or negative

Combine 1 & 2

y-2 < 2y-6 (you can do this since X is greater than Y-2. So if X is less than 2Y-6 ... then by definition Y-2 will be less than 2Y-6)

Simplify
y-2 < 2y-6
y < 2y - 4
y>4

From statement 1we know that
x > y-2 .. so X>2

both X & Y are positive. XY must be positive. Answer is C

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by crak.gmat » Sun Aug 24, 2008 6:01 pm
Thanks for the detailed explanation. Very helpful

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by mberkowitz » Sat Oct 11, 2008 1:05 pm
I'm not sure if anybody is still watching this post, but if so,

what if this weren't so convenient and we weren't able to combine the inequalities as done by LSB for part C. would it be best to plug numbers? whats the fastest way to tackle this?

thanks.

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by raju232007 » Sat Oct 11, 2008 9:32 pm
In most of the inequality problems you can just combine the statements and find the solution.But never forget the basic rule that whenever both sides of an inequality is multiplied or divided by a negative number the sign is reversed..All you have to worry about is absolute value problems which can sometimes pose a problem..Even problems of such type can be easily tackled using Ian Stewart's approach..

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by 4meonly » Sat Oct 11, 2008 11:11 pm
you can also make substraction (1) from (2)
1. x-y>-2
2. x-2y<-6


(1)
x+2<y
(2)
x+6<2y

Substracting:
4<y

Some variation to LSB's approach

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by raju232007 » Sun Oct 12, 2008 12:01 am
@ 4meonly....I think inequalities can be altered only by addition....Please correct me if I am wrong..

And the equations you have posted are incorrect

The 1st statement is x-y>-2 which can be altered to -x+y<2 (1) and not x+y<2 as you had posted earlier

The 2nd statement is x-2y<-6 (2)

Adding both the statements we get -y<-4 which is nothing but y>4

From the 1st statement we know that x>y-2 so x is also positive

Hence the ans is C

I would also request a piece of advice from the experts regarding altering the inequalities to deduce a solution...Kindly help

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by raju232007 » Tue Oct 14, 2008 4:32 am
I still haven't got a response..Can the inequalities be altered only by addition or can subtraction be used in some cases?....I kindly request the experts to share their thoughts on this...Pls help

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by parallel_chase » Tue Oct 14, 2008 9:01 am
raju232007 wrote:I still haven't got a response..Can the inequalities be altered only by addition or can subtraction be used in some cases?....I kindly request the experts to share their thoughts on this...Pls help

Inequalities can only be added to each other, they cannot be subtracted to each other in any case.
No rest for the Wicked....

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by cubicle_bound_misfit » Tue Oct 14, 2008 9:36 pm
suppose you have

1 x < ay +c
2 x> by +k

to substract

first make 2 like

-x < -(by +k)

and then add , remember for addition you need both the inequalities to have same gt or lt sign.

hope that helps.
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